In a breeding program a cross was made between two true breeding cow-pea types: one with round seeds and the other with wrinkled seed. If roundness is dominant why wrinkleness is recessive, in the first filial generation all the seeds produced will be
- 25% wrinkled, 75% round
- 100% wrinkled
- 50% wrinkled, 50% round
- 75% wrinkled, 25% round
-
100% round
The correct answer is: E
Explanation
Owing to the dominance of roundness, the crossing of the two seeds regularly would see all the offsprings having mixed genes but will be round.
Let RR = round seeds while RR = wrinkled seed
In the first filial generation, if we cross RR x rr
We'll have Rr, Rr, Rr, Rr
Remember that RR is dominant while rr is recessive
Therefore, All the four offsprings will be Dominant Round i.e 100% Round