The initial volume of water poured into 60g bag of dry soil was 50ml and the amount that drained through was 35ml. The percentage water content of the fully soaked soil is therefore
- 46.7
- 25.0
- 20.0
-
30.0
- 58.3
The correct answer is: D
Explanation
% water content of fully soaked sand = \(\frac{ 50 - 35}{50} \times 100\)
= \(\frac{ 15}{50} \times 100\) = 30.0.