A man and his wife are both heterozyous for the sickle-cell trait. The likely percentage of their offspring that will be either carriers or sicklers is
-
75%
- 50%
- 25%
- 100%
The correct answer is: A
Explanation
An heterozygote for sickle-cell anaemia = AS
Crossing two AS persons, we have one AA, two AS and one SS.
\(\therefore\) The probability that the children are either carriers or sicklers = \(\frac{3}{4}\)
= 75%