In an experiment to determine the percentage of humus and water in a soil sample, the following results were obtained
Weight of the evaporating basin alone = 80.5g
Weight of basin and soil = 101.5g
Weight after drying the soil in the oven = 99.0g
Weight of basin and roasted soil = 95.5g
The percentage of humus in the soil sample is
-
16.7%
- 17.6%
- 26.7%
- 16.2%
The correct answer is: A
Explanation
Mass of Soil = 101.5 - 80.5 = 21.0gMass of humus = (99.0 - 95.5)g = 3.5g
% of humus = \(\frac{3.5}{21.0} \times \frac{100}{1}}
= 16.7%
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