When sickle cell carrier marries a normal woman, the probability of them having a normal offspring is
- 0.75
- 0.25
-
0.5
- .1
The correct answer is: C
Explanation
A sickle cell carrier (AS) and a normal woman (AA), when crossed will yield:
2 normal offsprings (AA) and 2 sickle cell carrier (AS).
Hence, the probability of a normal child = \(\frac{2}{4}\)
= \(0.5\)
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