The initial volume of water poured into a bag of dry soil was 50ml and the amount that drained through was 35mI. The percentage water content of the fully soaked soil is therefore?
- 46.7
- 25.0
- 20.0
-
30.0
The correct answer is: D
Explanation
Percentage of water content (retained) = \(\frac{Water absorbed}{Weight of soil} * 100\)
→ \(\frac{50 - 35}{50} * 100\)
= 30%
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