\(50cm^{3}\) of hydrogen are sparked with \(20cm^{3}\) of oxygen at \(100°C\) and \(1atm\) . The total volume of the residual gases in
-
50 cm3
- 10 cm3
- 40 cm3
- 30 cm3
- 70 cm3
The correct answer is: A
Explanation
The equation of the reaction is:
\(2H_{{2}{(g)}} + O_{{2}{(g)}} = 2H_{2}O_{(g)}\)
Before Sparking we have : \(50cm^{3} : 20cm^{3}\)
On Sparking, \(40cm^{3} : 20cm^{3} : 40cm^{3}\)
After Sparking, we have \(10cm^{3} : 0 : 40cm^{3}\)
Hence, the volume of residual gases = \((10+40)cm^{3} = 50cm^{3}\)