How many grams of HBr would exactly be required to react with 2 g of propyne? (C =12, H=1, Br = 80)
- 4. 1 g
- 6. 1 g
-
8. 1g
- 16.2g
The correct answer is: C
Explanation
2HBr + C3H4 \(\to\) C3H6 + 2Br
162gms of HBr reacts with 40gms of propyne 2gms of propyne will react with
\(\frac{162}{40} \times \frac{2}{1}\) = 8.1gms HBr