12 g of solid protassium chlorate (KCIO) were added to 40 g of water and heated to dissolve all the solid. As the solution cools, crystals of potassium chlorate at 66 oC. The solubility of potassium chlorate at 66 oC is therefore?
- 66
- 33
- 10
- 20
-
30
The correct answer is: E
Explanation
solubility = \(\frac{solute x 100}{solvent}\)
The solubility of KClO3 at 66oC will be \(\frac{12}{40} \times \frac{100}{1}\)
= 30