Consider the following exothermic reaction \(2SO_{2(g)} + O_{2(g)} = 2SO_{3(g)}\) . If the temperature of the reaction is reduced from 800ºC to 500ºC, and no other change takes place, then
The correct answer is: C
Explanation
reducing the temperature from 800ºc to 500ºc will favour forward reaction according to Le Chatelier's principle hence the concentration of \(SO_3\) increases.