If one mole of aluminium contains 6 x 1023 atoms of aluminium, how many atoms are contained in 0.9g of aluminium?
(Al = 27)
- 1.0 x 1021
- 6.6 x 1021
-
2.0 x 1022
- 1.0 x 1022
- 5.4 x 1023
The correct answer is: C
Explanation
1 Mole or 27 gms of Al contains 6 x 1021 atoms0.9 gms of Al will contain (6 x 1023 x 0 g)/(27 1) = 0.2 x 1023 or 1022