0.07g of a hydride of carbon occupies 56.0cm3 at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)
- CH4
- C2H2
-
C2H4
- C2H6
- C3H8
The correct answer is: C
Explanation
% of H2 = 14.29
% of C = 85.71
Divided by At wts
For H = (14.29)/(1) = 14.29
For C = (85.71)/(12) = 7.14
Dividing by smallest number we have the following:
For H (14.29)/(7.14) = 2
For C = (7.14)/(7.14) = 1
Emperical formula of the comp = CH2
wt of hydride that will occupy 22400 cm is 22400 x 0.7
56 = 28 = mole wt of hydride
X(CH2) = 28
X(12 + 2) = 28 i.e 14x = 28x = 2
The formula of hydrocarbon is therefore C2H4