Which volume of 0.5 M H 2SO4 will exactly neutralize 20 cm 3 of 0.1 M NaOH solution?
-
2.0 cm 3
- 5.0 cm 3
- 6.8 cm 3
- 8.3 cm 3
- 10.4 cm 3
The correct answer is: A
Explanation
\(\frac{C_AV_A}{C_bV_b} = \frac{1}{2}\)\(frac{0.5 \times V_A}{0.1 \times 20} = \frac{1}{2}\)
\(V_A = \frac{0.1 \times 20}{2 \times 0.5} = \frac{1.0}{0.5)\)
= 2cm2