3. 06 g of a sample of potassium trioxochlorate (V) (KCIO\(_3\)) was required to make a saturated solution with 10cm\(^3\) of water at 25°C. The solubility of the salt at 25°C is [K =39, Cl = 35.5, O = 16]
- 5.0 moles dm3
- 3.0 moles dm3
-
2.5 moles dm3
- 1.0 molesv
- 0.5 moles dm3
The correct answer is: C
Explanation
Molar mass of KCIO\(_3\) = 122.5 g/mol
3.06g = 10
xg = 1000
\(frac{3.06 * 1000}{10}\)
= 306g
Molar conc = \(frac{Mass conc}{Molar mass}\)
Molar conc = \(frac{306}{122.5}\)
= 2.497mol/dm\(^3\)