Given that the molecular mass of iron is 56 and that of oxygen is 16, how many moles of iron(iii)oxide will be contained in 1kg of the compound?
- 25.0 moles
- 12.5 moless
-
6.25 moles
- 3.125 moles
- 0.625 moles
The correct answer is: C
Explanation
Fe2O3 = 56 x 2 + 48 = 160 = 1 moles1000gm will contain \(\frac{1000}{160}\) = 6.25 moles