A certain volume of gas at 298k is heated such that its volume and pressure are now four times the original values. What is the new temperature?
- 18.6k
- 100.0k
- 298.0k
- 1192.0k
-
4768.0k
The correct answer is: E
Explanation
\(\frac{P_1V_1}{T_1} = \frac{4P_1 \times 4V_1}{T_2}\)i.e \(\frac{P_1V_1}{298} = \frac{4P_1 \times 4V_1}{T_2}\)
T2 = \(\frac{298 \times 4P_1 \times 4V_1}{P_1V_1}\)
= 298 + 16 = 4768.0k