Copper sulphate solution is electolysed using platinum electrodes A. current of 0.193 amperes is passed for 2hrs. How many grams of copper are deposited? (cu = 63.5, F = 96500 coulombs)
-
0.457g
- 0.500g
- 0.882g
- 0.914g
- 1.00g
The correct answer is: A
Explanation
Time = 2hrs = 120mins = 120 x 60secs =7200secs.
current = 0.193amps
Quantity of electricity = 7200 x 0.193 = 1389.6
2 x 96,500 deposits 63.5 gms of Cu
1389.6 will deposit \(\frac{63.5 \times 1389.6}{2 \times 96500}\)
= 0.457g