20 cm3 of 1.0 molar NH4OH solution when neutralized with 20.05cm3 of 0.1 molar HCl liberated -102 joules of heat. Calculate the heat of neutralization of NH4OH?
-
-51.O KJ mol-
- +57.3 KJ mol-
- +57.O KJ mol-
- +51.0 KJ mol-
The correct answer is: A
Explanation
NH4OH = 20cm of 0.1 mNH4 + HCl → NH4Cl = H2O
Heat of Neutralization of NH4OH
= \(\frac{-102}{2}\) = -51.0 KJ mole-1