The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro’s Number =…

Chemistry JAMB 1986

The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro’s Number = 6.02 x 1023]

  • 6.02 x 1022 checkmark
  • 5.85 x 1023
  • 6.02 x 1023
  • 5.85 x 1024

The correct answer is: A

Explanation

The number of atoms of chloride present in 5.85g of NaCl is 5.85 x 6.0 x 1023

= 6.02 x 1022
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