The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro’s Number = 6.02 x 1023]
-
6.02 x 1022
- 5.85 x 1023
- 6.02 x 1023
- 5.85 x 1024
The correct answer is: A
Explanation
The number of atoms of chloride present in 5.85g of NaCl is 5.85 x 6.0 x 1023= 6.02 x 1022