If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3
of HCl, what is the molarity of the HCl?
-
0.094 M
- 0.150 M
- 0.940 M
- 1.500 M
The correct answer is: A
Explanation
NaOH + HCl → NaCl + H2O moles ratio = 1/1↔ (MaVa) / Mb x 39.45 = 0.094