One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?
(G.M.V = 22.4 dm3 mol-1)
- 112.0 dm3
-
67.2 dm3
- 56.0 dm3
- 44.8 dm3
The correct answer is: B
Explanation
C3H8 + 5O2 → 3CO2 + 4H2OWhen the mixture is ignited CO2 is collected as product. From the equation 33 moles of CO2 is produced which equals 3 x 2.4 dm3 = 67.2 dm3 at S.T.P