Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of…

Home » Past Questions » Chemistry » Jamb » 1989 » Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of…
Chemistry JAMB 1989

Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of the compound formed is?

  • XY
  • YX
  • X2Y3
  • Y2X3 checkmark

The correct answer is: D

Explanation

\(\frac{\text{Element X}}{1s^22s^21p^4}\)

Valency of X is 2


\(\frac{\text{Element Y}}{1s^22s^22p^63s^23P^1}\)

valency of Y is 3

There is an exchange of valency when a compound is being formed. Hence, we have Y\(_2\)X\(_3\)

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