The same current is passed for the same time through solutions of AgNO3 and CuSO4 connected in series. How much silver will be deposited if 1.0 g of copper is produced?
[Cu = 63.5, S = 32, O = 16, Ag = 108, N = 14]
- 1.7 g
-
3.4 g
- 6. 8 g
- 13. 6 g
The correct answer is: B
Explanation
From Faraday;s second law of electrolysis\(\frac{\text{Mass of silver deposited}}{\text{Mass of copper deposited}}\) = \(\frac{\text{Equivalent mass of silver}}{\text{Equivalent mass of copper}}\)
\(\frac{\text{Mass of silver deposited}}{1.0g}\) = \(\frac{108}{63.5}\)
= 31.75g
Copper is devalent = Cu2+
Mass of silver deposited = \(\frac{108g}{31.75g}\)
= 3.30g