0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution….

Chemistry JAMB 1990

0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution.
Calculate the number of moles of nickel that will be deposited by 0.4 faraday?

(Ni = 58.7)

  • 0.20 checkmark
  • 0.30
  • 0.04
  • 5.87

The correct answer is: A

Explanation

0.1F ↔ 2.95 g Ni = 0.4F ↔ 11.8 g Ni

No of moles = (11.8)/(58.2) = 0.20 moles
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