0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution.
Calculate the number of moles of nickel that will be deposited by 0.4 faraday?
(Ni = 58.7)
-
0.20
- 0.30
- 0.04
- 5.87
The correct answer is: A
Explanation
0.1F ↔ 2.95 g Ni = 0.4F ↔ 11.8 g NiNo of moles = (11.8)/(58.2) = 0.20 moles