30cm\(^3\) of oxygen at 10 atmospheres pressure is placed in a 20 cm\(^3\) container. Calculate the new pressure if temperature is kept constant?
- 6.7 atm
-
15.0 atm
- 60.0 atm
- 66. 0 atm
The correct answer is: B
Explanation
P\(_1\)V\(_1\) = P\(_2\)V\(_2\) (where T is kept constant)
30 x 10 = P\(_2\) x 20
P\(_2\) = \(\frac{30 \times 10}{20}\)
= 15.0 atm