Cr2O72-(aq) + 14H+(aq) + 6l-(aq) → 2Cr3+(aq) + 3l

Chemistry JAMB 1995

Cr2O72-(aq) + 14H+(aq) + 6l–(aq) → 2Cr3+(aq) + 3l(g) + 7H2O(I).
The change in the oxidation number of oxygen in the equation above is?

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The correct answer is: A

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