A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is?
-
0.90 atm
- 0.80 atm
- 0.70 atm
- 0.60 atm
The correct answer is: A
Explanation
Total no mole = 0.2 + 0.2 + 0.3 = 0.7Partial pressure of He = (0.3)/(0.7) x 2.1 =0.90