Given that 15.00 cm3 of H2
SO4 was required to completely neutralize 25.00 cm3 of 0.125 mol dm-3 NaOH, calculate the molar concentration of the acid solution:
- 0.925 mol dm-3
- 0.156mol dm-3
-
0.104 mol dm-3
- 0.023 mol dm-3
The correct answer is: C
Explanation
H2SO4 + 2NaOH → Na2SO4 + 2H2O(MaVa)/(MBVB) (1)/(2) (MA x 15)/(0.125 x25) = 1/2
MA = 0.104