A sample of a substance containing only C and H burns in excess O2 to yield 4.4g of CO2
and 2.7 g of H2O. The empirical formula of a substance is?
(C = 12, O = 16, H = 1)
-
CH3
- CH2
- CH4
- C2H24
The correct answer is: A
Explanation
CxHy + (x + y/4)O2 = XCO2 + (y/2)H2O4.4 2.7
according to the equation 44x = 9y
Carbon Hydrogen
mole given ratio = (44)/(44), (2.7)/(9) = 0.1,0.3
Empirical formula = (0.1)/(0.1), (0.3)/(o.1) = 1,3 ; CH3