8.0 g of an element X react with an excess of copper (ll) tetraoxosulphate (lV) solution to deposit 21.3 g of copper. The correct equation for the reaction is?
(Cu = 64).
-
X(s) + CuSO4(aq) → Cu(s) + XSO4(aq)
- X(s) + 2CuSO4(aq) → 2Cu(s) + X(SO4)2(aq)
- 2X(s) + CuSO4(aq) → Cu(s) + X2SO4(aq)
- 2X(s) + 3CuSO4(aq) → 3Cu(s) + X2(SO4)3(aq)