56.00cm3 of a gas at S.T.P. weighed 0.11g. What is the vapour density of the gas?
[Molar volume of a gas at S.T.P = 22.4dm3]
- 11.00
-
22.00
- 33.00
- 44.00
The correct answer is: B
Explanation
56.00cm3 of a gas at S.T.P weighed 0.11gMolar volume of the gas = 22.4dm3 = 22400cm3
molar mass = (22400 x 0.11)/56
molar mass = 2464/56 = 44
Vapour density = Molar mass/2 = 44/2 = 22