Which is the temperature of a given mass of a gas initially at 0°C and 9 atm, if the pressure is reduced to 3 atm at constant volume?
-
91K
- 182K
- 273K
- 819K
The correct answer is: A
Explanation
From P1/T1 = P2/T2 = 9/273 = 3/T2T2 x 9 = 273 x 3
T2 = (273 x 3)/9
T2 = 91K