The correct order of increasing oxidation number of the transition metal ions for the compounds K2Cr2O7, V2O5 and KMnO4 is
V2O5 < K2Cr2O7 < KMnO4
K2Cr2O7 < KMnO4 < V2O5
KMnO4 < K2Cr2O7 < V2O5
KMnO4 < V2O5 < K2Cr2O7
The correct answer is: A
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