RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation…

Chemistry JAMB 1999

RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that

  • the heat content of the reactants is lower than that of the products
  • the heat content of the reactants is higher than that of the products checkmark
  • the reaction is slow
  • a large amount of heat is absorbed

The correct answer is: B

Explanation

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