How many moles of HCl will be required to react with potassium heptaoxodichromate (VI) to produce 3 moles of chlorine?
-
14
- 12
- 11
- 10
The correct answer is: A
Explanation
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + HCl → Cl\(_{2}\) + KCl + CrCl\(_{3}\) + H\(_{2}\)O
Balancing the equation, we have
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + 14HCl → 3Cl\(_{2}\) + 2KCl + 2CrCl\(_{3}\) + 7H\(_{2}\)O
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