The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is
- 12.40
-
13.40
- 14.40
- 14.60
The correct answer is: B
Explanation
pOH = -log [2.5 x 10-1]
= -log[-0.3979 + 1]
= 13.40
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