The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is
The correct answer is: B
Explanation
pOH = -log [2.5 x 10-1]
= -log[-0.3979 + 1]
= 13.40
There is an explanation video available .
The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is
pOH = -log [2.5 x 10-1]
= -log[-0.3979 + 1]
= 13.40
There is an explanation video available .