MnO\(_{4(aq)}^{-1}\) + 8H\(^+ _{(aq)}\) + Y → Mn\(^{2+} _{(aq)}\) + 4H\(_2\)O\(_{(l)}\) Y in the equation…

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Chemistry JAMB 2000

MnO\(_{4(aq)}^{-1}\) + 8H\(^+ _{(aq)}\) + Y → Mn\(^{2+} _{(aq)}\) + 4H\(_2\)O\(_{(l)}\)
Y in the equation above represents

  • 2e-
  • 3e-
  • 5e- checkmark
  • 7e-

The correct answer is: C

Explanation

We want the number of charges on both sides of the equation to be the same. 

i.e. number of charges on the reactant side = the number of charges on the product side. 

                                                                    -1 + 8  =  2

                                                                            7 = 2

difference in number of charges = 5, hence Y = 5.

 

 

There is an explanation video available .

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