(1/2)Zn2+(aq) + e- → (1/2) Zn(s)
In the reaction above, calculate the quantity of electricity required to discharge zinc.
[F = 96 500 C mol-1]
- 0.965 x 104C
- 4.820 x 104C
-
9.650 x 104C
- 48.200 x 104C
The correct answer is: C
Explanation
1 mol → 96500 x 2
0.5 mol → X
X = 0.5 x 96500 x 2
= 9.650 x 104C
There is an explanation video available .