What mass of water is produced when 8.0g of hydrogen reacts with excess oxygen?
[H = 1, O = 16]
- 36.0g
- 8.0g
-
72.0g
- 16.0g
The correct answer is: C
Explanation
\(2H_2 + O_2 → 2H_2O\)
4g → 36g
8g → X
X → \(\frac{ 36 \times8}{4}\)
= 72.0g
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