An oxide XO\(_2\) has a vapour density of 32. What is the atomic mass of X?
-
32
- 20
- 14
- 12
The correct answer is: A
Explanation
Relative molecular mass of XO\(_2\) = 2 × vapour density
Relative molecular mass → (2 x 32) = 64
Atomic mass of X:
X + [16 x 2] = 64
X = 64 - 32
= 32
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