What is the decrease in volume of air when pyrogallol is shaken with 30.00cm\(^3\) of air ?
- 15.00cm3
-
6.30cm3
- 0.63cm3
- 0.06cm3
The correct answer is: B
Explanation
% Volume of O\)_2\) in air = 21%
∴(\(\frac{21}{100}\times30\)) = 6.30 cm\(^3\)
There is an explanation video available .