PCl5(g) ↔ PCl3(g) + Cl2(g)
In the reaction above, a decrease in pressure will
- Decelerate the reaction
-
Increase the yield of PCl3
- Increase the yield of PCl5
- Accelerate the reaction
The correct answer is: B
Explanation
First, calculate the total number of number of moles of gaseous species only, on both sides.
i.e 1 mole on the LHS while 2 moles on RHS.
An increase in pressure will favour the side with the lesser value of the total number of moles while a decrease in pressure will favour the side with the higher number of moles i.e the RHS. Hence,increasing the yield of PCl\(_3\).