If 0.75 mole of cyclopropane and 0.66 mole of oxygen are mixed in vessel with a total pressure of 0.7 atmosphere, what is the partial pressure of oxygen in the mixture
- 0.44 atmosphere
- 0.22 atmosphere
- 0.55 atmosphere
-
0.33 atmosphere
The correct answer is: D
Explanation
Parameters given:
Number of moles of Cyclopropane, N\(_c\) = 0.75 mole
Number of moles of Oxygen, N\(_o\) = 0.66 mole
Total pressure of mixture of gases, P\(_T\) = 0.70 atm
Partial pressure of Oxygen in the mixture, P\(_O\) = ?
Using the formula, P\(_O\) = \(\frac{N_o}{{N_o} + {N_c}}\) X P\(_T\)
= \(\frac{0.66}{{0.66} + {0.75}}\) X 0.70
= \(\frac{0.66}{1.41}\) X 0.70
= 0.3276
= 0.33 atm