2H2 + O22 → H2+O ΔH = -571kJ In the equation above, how much heat…

Chemistry JAMB 2005

2H2 + O22 → H2+O ΔH = -571kJ
In the equation above, how much heat will be liberated if 12.0g of hydrogen is burnt in excess oxygen?

  • -1142 kJ
  • -571 kJ
  • +1142 kJ
  • -1713 kJ checkmark

The correct answer is: D

Explanation

2H2 + O22 → H2+O ΔH = -571kJ
4.0g of Hydrogen burn in air to produce -571 kJ
∴ 12.0s of Hydrogen will burn in air to produce
(12 * -571)/4 = -1713kJ
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