The volume of 2.5 moles of oxygen at s.t.p is
[Molar volume of a gas at s.t.p = 22.4 dm3]
- 50.0 dm3
- 84.0 dm3
- 28.0 dm3
-
56.0 dm3
The correct answer is: D
Explanation
1 mole of gas at s.t.p = 22.42.5 moles → 2.5 * 22.4 = 56.00 dm3