In the electrolysis of CuSO4(g) using platinum electrodes, the reaction at the anode is

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Chemistry JAMB 2006

In the electrolysis of CuSO4(g) using platinum electrodes, the reaction at the anode is

  • 4H+ + 4e- → 2H2
  • 4OH- + 4e- → 2H2O + O2 checkmark
  • 2OH - 2e- → 2OH
  • 2OH- + 2OH- → 2H2O + O2

The correct answer is: B

Explanation

4OH<sup>-</sup> + 4e<sup>-</sup> → 2H<sub>2</sub>O + O<sub>2</sub> is the reaction of sun at the anode in the electrolysis of CuSO4 (g) 

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