Calculate the mass of chlorine gas which occupies a volume of 1.12dm3 at s.t.p
[Cl = 35.5, molar volume of gas at s.t.p = 22.4 dm3
- 15.50 g
- 7.10 g
-
3.55 g
- 1.80 g
The correct answer is: C
Explanation
2 * 35.5g of chlorine has a volume of 22.4 dm3 at s.t.p∴ xg of chlorine will have a volume of 1.12 dm3
x = (1.12 * 35.5 * 2)/22.4 = 3.55g