How many electrons are in the L shell of \(^{31}_{15}\)P?
- 5
-
8
- 18
- 2
The correct answer is: B
Explanation
N.B :
Atomic number = no. of protons = no. of electrons = 15
Orbital configuration of the neutral atom of the element = 2, 8, 5 which represents the shells starting from the first which is K, L, M respectively. i.e
K = 2, L = 8 , M = 5.
Therefore, the L - shell has 8 electrons.