What weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution?
[Na = 23, Cl = 35.5]
The correct answer is: B
Explanation
Molar mass of Nacl = 23 + 35.5 = 58.5 g/molNumber of moles of Nacl = conc. in mol/dm3
x vol. in dm3
= 1.5 * 2.0 = 3.0 moles
1 mole of NaCl has a weight of 58.5 * 3
= 175.5g