What weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution? [Na…

Chemistry JAMB 2007

What weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution?
[Na = 23, Cl = 35.5]

  • 116 g
  • 175 g checkmark
  • 87 g
  • 58 g

The correct answer is: B

Explanation

Molar mass of Nacl = 23 + 35.5 = 58.5 g/mol
Number of moles of Nacl = conc. in mol/dm3
x vol. in dm3
= 1.5 * 2.0 = 3.0 moles
1 mole of NaCl has a weight of 58.5 * 3
= 175.5g
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