117.0g of sodium chloride was dissolved in 1.0dm3 of distilled water at 25°C. Determine the solubility in mol dm-3 of sodium chloride at that temperature
[Na = 23, Cl = 35.5]
- 1.0
-
2.0
- 3.0
- 4.0
The correct answer is: B
Explanation
Relative molecular mass of NaCl = 23 + 35.5 = 58.5 g/mol
No. of mole of NaCl = 117/58.5 = 2.0 mol
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